asbestos iron
somewhat hard physics question?
Given a slab of material that is 1.2 m^2 and 2.4 × 10^-2 m thick,
(a) what is the thermal resistance if the material is asbestos?
(b) What is the thermal resistance if the material is iron?
(c) What is the thermal resistance if the material is copper?
Units in K/W
If you have values for the thermal resistivities of these materials, this is actually an easy problem. It may be a little harder if you must convert the thermal resistivities to deg K-m / W from some other units. If k is the thermal resistivity of the material and θ is the thermal resistance across a slab of this material with the energy being conducted through its thickness, then
θ = k*t/A, where t is the thickness of the material and A is its area. Values for t and A are given in the problem. I assume that your textbook has values for k somewhere in the chapter or in the appendix. If not, you can find these values on the net.
Against Me!- Walking Is Still Honest
